(Sorry, I may have misunderstood.)
If so, the resistor is limiting the current to such a low value that the motor won't turn.
Connect the motor directly between the collector and the supply (put a diode acoross it so that the inductive transients from the motor don't damage the transistor).
Connect the LED and resistor in series, and put the series combination across the motor.
Remember also that the base current times the transistor gain must exceed the current the motor draws.
Because you were doing it wrong, motor would not run due to most voltage was dropped down by the 470 ohm since you hook them in series. This is the basic rule from series circuit and why you did not understand it well ???
Parallel 470 ohm and LED to motor shall solve your trouble.
place a 9 v lamp between +9 v battery and transistor collector ....
is it light on ? ....if no ...increase base current with divider resistors .(study increasing base current.)
when transistor acts as a switch , Vce is about 1 volt....measure it ..
now place motor...a series an led and a resistor connect in parallel with motor wires...
How much current does the motor take? Is the base current of the transistor large enough to ensure it is saturated?
I have a Mechatronics project in which I have to design a circuit that allows me to operate a motor ( Switch ON & OFF ) using a transistor (BJT) . The voltage provided is 9V
It is required to put a LED before the motor to see if the circuit is closed or open.
That means I have to put a resistor (at least 330 Ohms) before the LED in order not to burn it. But the thing is, When I put a resistor (470 Ohms) before the LED and close the circuit, the LED turns ON, but the motor doesn't work at all.
Can someone tell me what I'm doing wrong and how to fix it ?
Thanks
