V = constant = Φ*f
the higher the flux, the lower the frequency ....and vice versa
You need to be more specific about the context of your question. If you happen to be talking about an inductor or a transformer, then as the frequency of the AC input increases and with other things being equal, the maximum flux density created by the excitation current will diminish. This results from Faraday's law which shows that the magnetic flux is proportional to the time integral of the applied voltage. As frequency increases, the integration period is shorter and thus the peak flux created is diminished.
This is why highly portable electrical equipment is sometimes designed to operate at 400 Hz rather than the more common 60Hz- it reduces the amount of iron required for transformer cores.
Yes you are right. Flux density = voltage/frequency. This relation comes from e.m.f equation of a transformer.
E=4.44B.A.F.T.
Where B(flux density) =flux/unit area, F= frequency, T= no. Of turns
No such relationship arises from physics alone.
The two quantities are not interdependent in any such way,
although the frequency of oscillations in magnetic flux
density would drive the frequency of everything else in a circuit.
However, it's perfectly possible that in certain electronic DEVICES,
higher frequency decreases flux density, etc.
v= 4.44n.f.flux
n= no of turns of winding
you said flux is inversely prop to freq which us true but not entirely in electric machines we increase freq but at the same time we have to decrease voltage...v/f= fkux...which have to be const...bcoz we design machines to work at const flux...increase influx saturate the core and decrease in flux reduce flux density which reduce generated voltage...
I had heard there is a relation between flux density and frequency. That is the relation between flux density and frequency is inversely proportional . If the frequency increases the flux density decreases and vice verse My doubt is that is my conclusion is correct?. Can I get the correct answer?.
