Ya canna change the laws a physics!
If you want to draw 1A from a 10V DC source, that pretty much defines the power output, and thus the amount of heat per second that you need to dissipate. To not produce that much heat would be to draw less current.
It is the corollary equivalent of trying to walk up some stairs without using any energy. Except you are trying to fall down stairs without losing any potential energy.
Added:
You will *always* end up with the same heat. You can spread it over more parts so each part is cooler but you said you had limited space.
Running a fan is OK (although it seems mighty big compared to a resistor) and it will move the heat away but you are never going to find a 10V fan that draws 1A, so just use it to cool the resistor.
Small fans should come with a rated current or power for a particular voltage (P=VI) and the chances are that the current drawn will be much, much smaller than 1A, so you will still need the resistor.
It doesn't make any sense that your computer will shut off if the load on the 10 VDC supply drops below 1 amp. Anyway, that power (10 volts times 1 amp) cannot be stored magnetically, because there is no practical way to do that. 10 watts is 10 Joules/second so in just 1 minute you world have to store 600 Joules. Figure out how large and inductor that would take. Now figure out what 1 hour would take.
the heat is produced because you select resistor as the 'load'. thus all energy is converted to heat (I^2Rt) since energy is conserved. Change your load to DC fan. it will convert the incoming energy as heat, and magnetic and mechanic. this approach may reduce the produce heat while you get cooling in the same time.
You can drop from 10V to 2V with DCDC converter; but asking to draw 1Amp while converting you must back to eenrgy conservaton. V1I1=V2I2. if you need 1 Amps draws at 10V, you must have 5 amps load at 2volt DC.
Why make thing so complicated ? JUST DROP ALL RESISTOR LOADS INTO A LARGE TANK OF COLD WATER to dissipate the heat. Also it is a free hot water source for you to make coffee while working in field work.
Convert it into electro-magnet is also generate heat in choke.
Drop it down from 10V into 2V with regulator is also generate heat.
There are electronic loads that are also grid connected inverters, ie they recycle the power back to the AC mains. However this is a very expensive and complicated solution.
http://smartpowerate.com/index.html
http://www.inteproate.com/lifeburn.php
http://www.heidenpower.com/en/products/e...
http://en.wikipedia.org/wiki/Grid-tie_in...
I have a field computer that has many outputs at 10v DC and looks to make sure 1 Amp is being drawn. If the current drops below 1A, the output shuts off.
For testing in the lab, I need to trick the computer by adding a resistive load that draws at least 1A. This is generating much more heat than I would like to deal with. (because of space limitations)
Is there a way to convert this electrical energy into magnetic energy such as an electromagnet and dissipate MUCH less heat in the process.
OR, is there a way to externally drop the voltage down to 2v while still drawing 1A? I can't have any back current going into the outputs.
