One unit of electricity is an average power of 1kW for 1 hour (or 0.1kW for 10 hours, and so on).
If the supply voltage is 230V, the power in watts is V * I. Thus a 2 amp load is 460W, and the time to use one unit is 1000W for one hour / 460W = 2.17 hours. There is no particular current, because time is also involved.
Another issue is power factor. The apparent power is V * I, which is in units of KVA. The real power is the same or less, depending on power factor (PF) of the load, which could be 1 for a heater, 0.8 for a motor, so:
kW = 1.25KVA * 0.8PF = 1kW
You only pay for true power (in most situations). A lower power factor causes more current that is not used as power, hence the name 'apparent power'.
Ampere depend only on the Load and the system voltage.
we have V = IR
V = voltage in Volts
I = Current in Ampere
R = load in Ohms
So current does not depend on Unit
Current I is a one of the element ot obtain Power,
By knowing the energy, we can calculate the current.
find the calculations below
Load Type Voltage PF Power V*PF Load(P/(V*PF)...
Resistive 230 1 1000 230 4.35 1 1000
Inductive 230 0.8 1000 184 5.43 1 1000
Note: Load can be one or More Load
Thus we can calculate the current by energy
"unt" is a UK term for kilowatt-hour, or kW-hr.
That is not convertible to amps, they are apples and oranges.
