A 300 ohm resistor in series with another 300. V =10V. What is the power in the system?

I=v/r





I=10/600 = 0.01667





P=v*i





P=10*0.01667= .1667

Power (P) = V * I = V^2 / R



R = 300 Ω + 300 Ω = 600 Ω



P = (10V)^2 / 600 Ω = 1/6 W

power=current *voltage.



calculate current first.



resistors are in series so eq. resistance = 300 + 300=600 ohm



now using ohms law I=v/r=10/600=.0166amp



p=.0166*10=.166 watt

W = 100 / 600 = 1/6 watt

A 300 ohm resistor in series with another 300. V =10V. What is the power in the system?